Amount Of Oxygen Needed To Oxidize 12.5 g Of Glucose

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Amount Of Oxygen Needed To Oxidize 12.5 g Of Glucose


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Strings (SiPjAjk) = S7P1A15     Base Sequence = 12735     String Sequence = 12735 - 1 - 15

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Amount Of Oxygen Needed To Oxidize 12.5 g Of Glucose
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Oxidation Of Glucose

The human body uses glucose as a source of energy. The oxidation reaction in the body is as stated in (figure 7.3).
Calculate the number of grams of oxygen needed to oxidize 12.5 g of glucose to carbon dioxide and water

The strings: S7P5A51 (Change - Physical).

The math:
Pj Problem of Interest is of type Containership (Mass).

Oxidation Of Glucose

From the balanced equation (figure 7.3),
Molecular mass of glucose require 6 moles of oxygen
Molecular mass of glucose = (12x6) + (1x12) + (16x6) = 180
So, 180 g of glucose require 6 moles of oxygen
Therefore 12.5 g of glucose require (12.5 x 6)/180 = 0.417 moles of oxygen
Convert moles of oxygen to grams of oxygen
1 mole of oxygen is equivalent to 32 g of oxygen
So, 0.417 mole of oxygen require (0.417 x 32) g = 13.3 g of oxygen
So, 13.3 g of oxygen is needed to oxidize 12.5 g of glucose to carbon dioxide and water.

The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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