Amount Of Oxygen Needed To Oxidize 12.5 g Of Glucose
TECTechnics Classroom   TECTechnics Overview

Expressions Of Pj Problems
Amount Of Oxygen Needed To Oxidize 12.5 g Of Glucose

Oxidation Of Glucose

The human body uses glucose as a source of energy. The oxidation reaction in the body is as stated in (figure 7.3).
Calculate the number of grams of oxygen needed to oxidize 12.5 g of glucose to carbon dioxide and water

The strings: S7P6A66 (grouping/interaction - Chemical). S7P1A15 (containership - mass)

The math:
Although several PjProblemStrings are at play, the
Pj Problem of Interest is of type Containership (Mass).

Oxidation Of Glucose

From the balanced equation (figure 7.3),
Molecular mass of glucose require 6 moles of oxygen
Molecular mass of glucose = (12x6) + (1x12) + (16x6) = 180
So, 180 g of glucose require 6 moles of oxygen
Therefore 12.5 g of glucose require (12.5 x 6)/180 = 0.417 moles of oxygen
Convert moles of oxygen to grams of oxygen
1 mole of oxygen is equivalent to 32 g of oxygen
So, 0.417 mole of oxygen require (0.417 x 32) g = 13.3 g of oxygen
So, 13.3 g of oxygen is needed to oxidize 12.5 g of glucose to carbon dioxide and water.

Math
What is Time?
St Augustine On Time
Bergson On Time
Heidegger On Time
Kant On Time
Sagay On Time
What is Space?
Newton On Space
Space Governance
Leaders
Imperfect Leaders
Essence Of Mathematics
Toolness Of Mathematics
The Number Line
Variables
Equations
Functions
The Windflower Saga
Who Am I?
Primordial Equilibrium
Primordial Care
Force Of Being
Forgiveness

Blessed are they that have not seen, and yet have believed. John 20:29

TECTechnic Logo, Kimberlee J. Benart | © 2000-2021 | All rights reserved | Founder and Site Programmer, Peter O. Sagay.