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Pj Problems - Overview

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Painting

Amount Of Oxygen Needed To Oxidize 12.5 g Of Glucose

The human body uses glucose as a source of energy. The oxidation reaction in the body is as stated in (figure 7.3).

Calculate the number of grams of oxygen needed to oxidize 12.5 g of glucose to carbon dioxide and water

**The strings**:
S_{7}P_{6}A_{66} (grouping/interaction - Chemical).
S_{7}P_{1}A_{15} (containership - mass)
**The math**:

Although several PjProblemStrings are at play, the

Pj Problem of Interest is of type *Containership* (Mass).

From the balanced equation (figure 7.3),

Molecular mass of glucose require 6 moles of oxygen

Molecular mass of glucose = (12x6) + (1x12) + (16x6) = 180

So, 180 g of glucose require 6 moles of oxygen

Therefore 12.5 g of glucose require (12.5 x 6)/180 = 0.417 moles of oxygen

Convert moles of oxygen to grams of oxygen

1 mole of oxygen is equivalent to 32 g of oxygen

So, 0.417 mole of oxygen require (0.417 x 32) g = 13.3 g of oxygen

So, 13.3 g of oxygen is needed to oxidize 12.5 g of glucose to carbon dioxide and water.

Math

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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Separation Of Variables As Solution Method For Homogeneous Heat Flow Equation

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The Universe is composed of *matter* and *radiant energy*. *Matter* is any kind of *mass-energy* that moves with velocities less than the velocity of light. *Radiant energy* is any kind of *mass-energy* that moves with the velocity of light.

Periodic Table

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How Matter Gets Composed (2)

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