Pj Problems - Overview
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A sample of glucose (C6H12O6), contains 1.250 x 1021 atoms of carbon
(a) Determine number of hydrogen atoms in the sample
(b) Determine number of molecules of glucose in the sample
(c) Determine number of moles of glucose in the sample
(d) Determine the mass of the glucose sample in grams.
S7P1A15 (containership - mass).
Pj Problem of Interest is of type containership (mas).
(a) The ratio of hydrogen atoms to carbon atoms in the formula of glucose is 2:1. One expects this ratio to hold in the distribution of atoms in the sample of glucose.
So, number of hydrogen atoms in sample of glucose:
= 2(1.25 x 1021) = 2.5 x 1021 atoms.
(b) I molecule of glucose contains 12 hydrogen atoms
So, number of glucose moles in sample:
= (2.5 x 1021 atoms)/12 = 0.2083 x 1021 = 2.08 x 1020 molecules.
(c)1 mole of glucose contains the Avogadro number of molecules = 6.02 x 1023
So, 2.08 x 1020 molecules of glucose contains:
(2.08 x 1020)/(6.02 x 1023) = 0.35 x 10-3 = 3.5 x 10-4 moles.
(d) 1 mole of glucose has 180 amu molar mass
So, 3.5 x 10-4 moles has:
= 180(3.5 x 10-4) = 0.063 grams of glucose.
The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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