Einstein's Energy Formula Applied To Uranium 235 Detonation

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Einstein's Energy Formula Applied To Uranium 235 Detonation

2 kg of Uranium 235 undergoes nuclear fission and liberates 1.646 x 10^{14} J of radiant energy and thermal energy. What is the mass of the material products of the reaction?

**The string**:

(a) S_{7}P_{1}A_{15} (Containership - Mass).
**The math**:

Pj Problem of Interest (PPI) is of the type *Containership*. We are interested in the mass of the products. However, the PPI is dependent on the fission (Splitting of atomic nucleus into approximatingly equal parts) which is of type *force*.

Einstein's Energy, E = mc^{2} (m = mass, c = velocity of light).

So, m = E/c^{2} = (1.646 x 10^{14})/(3 x 10^{8})^{2} = 0.00183 kg.

So, 2kg of Uranium 235 decreased by 0.00183 kg after the fission.

So, material mass of products of the reaction = 1.998 kg.

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