Mass Of Water Produced When 1 kg Of Fat In Camel's Hump Is Metabolized

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Mass Of Water Produced When 1 kg Of Fat In Camel's Hump Is Metabolized

The fat stored in the hump of a camel is a source of energy and water.

Calculate the mass of water produced when 1 kg of fat is metabolized. Assume the fat consists entirely of the animal fat, tristearin (C_{57}H_{110}O_{6}), and that tristearin reacts with oxygen to form only carbon dioxide and water.

**The strings**:
S_{7}P_{1}A_{15} (containership-mass).

S_{7}P_{6}A_{66} (grouping/interaction- chemical)
**The math**:

Pj Problem of Interest is of type *containership* (mass).

Balanced equation of tristearin and oxygen reaction:

2C_{57}H_{110}O_{6} + 163O_{2} -------> 114CO_{2} + 110H_{2}O

Molar mass of C_{57}H_{110}O_{6} = 57x12 + 1x110 + 16x6 = 684 + 110 + 96 = 890 g

So, 1 kg of C_{57}H_{110}O_{6} is the weight of 1000/890 = 1.124 moles of C_{57}H_{110}O_{6}.

2 moles of C_{57}H_{110}O_{6} produced 110 moles of water

So, 1.124 moles will produce (1.124 x 110)/2 = 61.82 moles of water

So, mass of water produced = 61.82 x 18 = 1112.76 g = 1.1 kg.

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