Determining Moles Of Water In One Mole Of Sodium Carbonate Hydrate.

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Determining Moles Of Water In One Mole Of Sodium Carbonate Hydrate

A 2.558 g sample of sodium carbonate hydrate (Na_{2}CO_{3}.xH_{2}O) is heated at 25^{o}C until O.948 g solid anhydrous sodium carbonate (Na_{2}CO_{3}) is left (All the water of hydration is lost).

Determine the value of x in Na_{2}CO_{3}.xH_{2}O. Where x is the number of moles of water in one mole of Na_{2}CO_{3}.

**The strings**:
S_{7}P_{1}A_{15} (containership - mass).

S_{7}P_{3}A_{32} (force - push).
**The math**:

Pj Problem of Interest is of type *containership* (mass).

Formula of sodium carbonate hydrate (also called washing soda) = Na_{2}CO_{3}.xH_{2}O.

Mass of water lost = 2.558 - 0.948 = 1.610 g.

Molar mass of water = 2 + 16 = 18

So, moles of water lost = 1.610/18 = 0.0894

Molar mass of sodium carbonate = 46 + 12 + 48 = 106 g.

So, moles of anhydrous sodium carbonate = 0.948/106 = 0.000894

So, mole ratio, Na_{2}CO_{3}:H_{2}O = 0.000894:00894 = 1:10.

So, x = 10.

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