Determining Moles Of Water In One Mole Of Sodium Carbonate Hydrate.
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Determining Moles Of Water In One Mole Of Sodium Carbonate Hydrate A 2.558 g sample of sodium carbonate hydrate (Na2CO3.xH2O) is heated at 25oC until O.948 g solid anhydrous sodium carbonate (Na2CO3) is left (All the water of hydration is lost).
Determine the value of x in Na2CO3.xH2O. Where x is the number of moles of water in one mole of Na2CO3.

The strings: S7P1A15 (containership - mass).
S7P3A32 (force - push).

The math:
Pj Problem of Interest is of type containership (mass). Formula of sodium carbonate hydrate (also called washing soda) = Na2CO3.xH2O.
Mass of water lost = 2.558 - 0.948 = 1.610 g.
Molar mass of water = 2 + 16 = 18
So, moles of water lost = 1.610/18 = 0.0894
Molar mass of sodium carbonate = 46 + 12 + 48 = 106 g.
So, moles of anhydrous sodium carbonate = 0.948/106 = 0.000894
So, mole ratio, Na2CO3:H2O = 0.000894:00894 = 1:10.
So, x = 10.

Math

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