Solution Composition - Molarity, Mass And Volume Calculations

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Solution Composition - Molarity, Mass And Volume Calculations

Solutions are homogeneous mixtures. Solutions consist of *solutes* and *solvents* (the more voluminous substance into which the solute dissolves). Solution concentration measures the amount of solute per liter of the solvent. *Molarity* is a commonly used measure of solution concentration.

Calculate:

(a) The number of grams of solute in 0.250 L of 0.150 M KBr

(b) The molar concentration of a solution containing 4.75 g of Ca(NO_{3})_{2} in 0.200 L

(c) The volume of 1.50 M Na_{3}PO_{4} in milliliters that contains 5.00 g of solute.

**The strings**:
S_{7}P_{1}A_{15} (containership - mass).
**The math**:

Pj Problem of Interest is of type *containership* (mass).
**(a)** 0.150 M of KBr = 0.150 mol/L of KBr

O.250 L of KBr contains (0.150)(0.250) = 0.0375 mol of KBr.

Molar mass of KBr = 39 + 80 =119 g

So, 119(0.0375) = 4.46 g of solute.
**(b)** Molar mass of Ca(NO_{3})_{2} = 40 + 28 + 96 = 164 g

So, 4.75 g of Ca(NO_{3})_{2} = 4.75/164 = 0.0290 mol

0.200 L contains 0.0290 mol of Ca(NO_{3})_{2}

So 1 liter contains 0.0290/0.200 = 0.233 mol

So, molar concentration = 0.145 M.
**(c)** Molar mass of Na_{3}PO_{4} = 23x3 + 31 + 16x4 = 69 + 31 + 64 = 164

So, moles of 5 g of Na_{3}PO_{4} = 5/164 = 0.0305 mol of Na_{3}PO_{4}

1.50 moles of Na_{3}PO_{4} in 1 liter

So, 0.0305 mol is in 0.0305/1.50 = 0.0203 L = 20.3 mL of 1.50 M of Na_{3}PO_{4}.

Math

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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