Weight Of Ice Melted By Heat Liberated From The Condensation Of Steam
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Weight Of Ice Melted By Heat Liberated From The Condensation Of Steam

Determine the weight of ice melted at 00C by the heat liberated when 100 grams of steam at 1000C condenses to liquid.
Heat of vaporization = 540 cal/g
Heat of fusion = 80 cal/g.

The strings:

S7P1A15 (containership - mass)

The math:
Pj Problem of Interest is of type containership. It is the mass of the melted ice that is of interest eventhough heat energy is operative.

Heat Of Vaporization: the quantity of heat required to vaporize 1 gram of a liquid substance at its boiling point at constant temperature.
Heat Of Fusion: the quantity of heat required to liquefy 1 gram of a solid substance at its melting point at constant temperature.

Amount of heat liberated by condensation 100 grams of steam at 1000C
= 540 x 100 = 54000 cal
Amount of heat required to melt 1 g of ice at 00C = 80 cal
So, weight of ice melted at 00C by 5400 cal = 54000/80 = 6.75 grams.

Math

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