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Weight Of Ice Melted By Heat Liberated From Steam Condensation


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Strings (SiPjAjk) = S7P1A15     Base Sequence = 12735     String Sequence = 12735 - 1 - 15



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Weight Of Ice Melted By Heat Liberated From Steam Condensation
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Determine the weight of ice melted at 00C by the heat liberated when 100 grams of steam at 1000C condenses to liquid.
Heat of vaporization = 540 cal/g
Heat of fusion = 80 cal/g.

The strings:

S7P1A15 (containership - mass)

The math:
Pj Problem of Interest is of type containership. It is the mass of the melted ice that is of interest eventhough heat energy is operative.

Heat Of Vaporization: the quantity of heat required to vaporize 1 gram of a liquid substance at its boiling point at constant temperature.
Heat Of Fusion: the quantity of heat required to liquefy 1 gram of a solid substance at its melting point at constant temperature.

Amount of heat liberated by condensation 100 grams of steam at 1000C
= 540 x 100 = 54000 cal
Amount of heat required to melt 1 g of ice at 00C = 80 cal
So, weight of ice melted at 00C by 5400 cal = 54000/80 = 6.75 grams.

The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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