Wavelength Of Light Determines The Color Of Light
Strings (SiPjAjk) = S7P2A21 Base Sequence = 12735 String Sequence = 12735 - 2 - 21
Figure 22.8 illustrates the different colors of the visible spectrum of light and their wavelength ranges. Suppose the frequency of light a potassium compound emits is 7.41 x 1014 Hz. What color in the visible spectrum would you expect to see when the potassium compound is heated in a Bunsen burner flame?
S7P2A21 (Identity - Physical Property)
Pj Problem of Interest is of type identity (physical property). Identity of color of emited light with a given frequency..
The equation that relates the frequency of light to its wavelength is as follows:
ν = c/λ
where ν is frequency of light, c is velocity of light (c = 3 x 1010 cm/sec) and λ is wavelength of light
So, 7.41 x 1014 = (3 x 1010)/λ
So, &lambda = (3 x 1010)/(7.41 x 1014) = 4.05 x 10-5 cm
= (4.05 x 10-5)108 = 4050 Å
Wavelenght of 4050 Å is within the violet region
So, expected color of light is violet.
The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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