Center Tapped Transformer

**Strings (S _{i}P_{j}A_{jk}) = S_{7}P_{3}A_{32} Base Sequence = 12735 String Sequence = 12735 - 3 - 32 **

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Center Tapped Transformer

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Figure 8.42 shows a center-tapped Transformer. The following information is given about the transformer:

Voltages and current are rms values.

Primary voltage = 4,800 V

Secondary voltage of 240 V is split (because transformer is center tap) into two voltages:

V_{2} = 120 V; V_{3} = 120 V.

Three resistive loads (R_{1}, R_{2}, R_{3}) are connected to the transformer (connection not shown in figure 8.42).

R_{1} is connected to the 240 V line.

R_{2} and R_{3} are connected to each of the 120 V lines.

Determine the power absorbed by each of the loads, if:

Power absorbed by R_{2} = P_{2}

Power absorbed by R_{1} = 5P_{2}

Power absorbed by R_{3} = 1.5P_{2}

Ccurrent through primary coil, I_{1} = 1.5625 A.

**The string**:

S_{7}P_{3}A_{32} (Force - Push).
**The math**:

Pj Problem of interest is of type *force*. The transformer steps up or steps down voltage. Voltage, power and energy problems are *force problems* (*force-push*).

The loads are all resistive, hence their respective power factor = 1.

So, voltages and currents are in phase.

Therefore rms amplitudes can be used in the calculations:

|S_{primary}| = |S_{secondary}|
= 4,800 x 1.5625 = 7,500.

So, 5P_{2} + P_{2} + 1.5P_{2} = 7,500

P_{2} = 1,000.

Hence, power absorbed by the resistors are as follows:

Powere absorbed by R_{1} = 5,000 W

Power absorbed by R_{2} = 1,000 W

Power absorbed by R_{3} = 1,500 W.

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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