Center Tapped Transformer

**Strings (S _{i}P_{j}A_{jk}) = S_{7}P_{3}A_{32} Base Sequence = 12735 String Sequence = 12735 - 3 - 32 **

Expressions Of Pj Problems

Center Tapped Transformer

Math

Pj Problems - Overview

Celestial Stars

The Number Line

Geometries

7 Spaces Of Interest - Overview

Triadic Unit Mesh

Creation

The Atom

Survival

Energy

Light

Heat

Sound

Music

Language

Stories

Work

States Of Matter

Buoyancy

Nuclear Reactions

Molecular Shapes

Electron Configurations

Chemical Bonds

Energy Conversion

Chemical Reactions

Electromagnetism

Continuity

Growth

Human-cells

Proteins

Nucleic Acids

COHN - Natures Engineering Of The Human Body

The Human-Body Systems

Vision

Walking

Behaviors

Sensors Sensings

Beauty

Faith, Love, Charity

Photosynthesis

Weather

Systems

Algorithms

Tools

Networks

Search

Differential Calculus

Antiderivative

Integral Calculus

Economies

Inflation

Markets

Money Supply

Painting

Figure 8.42 shows a center-tapped Transformer. The following information is given about the transformer:

Voltages and current are rms values.

Primary voltage = 4,800 V

Secondary voltage of 240 V is split (because transformer is center tap) into two voltages:

V_{2} = 120 V; V_{3} = 120 V.

Three resistive loads (R_{1}, R_{2}, R_{3}) are connected to the transformer (connection not shown in figure 8.42).

R_{1} is connected to the 240 V line.

R_{2} and R_{3} are connected to each of the 120 V lines.

Determine the power absorbed by each of the loads, if:

Power absorbed by R_{2} = P_{2}

Power absorbed by R_{1} = 5P_{2}

Power absorbed by R_{3} = 1.5P_{2}

Ccurrent through primary coil, I_{1} = 1.5625 A.

**The string**:

S_{7}P_{3}A_{32} (Force - Push).
**The math**:

Pj Problem of interest is of type *force*. The transformer steps up or steps down voltage. Voltage, power and energy problems are *force problems* (*force-push*).

The loads are all resistive, hence their respective power factor = 1.

So, voltages and currents are in phase.

Therefore rms amplitudes can be used in the calculations:

|S_{primary}| = |S_{secondary}|
= 4,800 x 1.5625 = 7,500.

So, 5P_{2} + P_{2} + 1.5P_{2} = 7,500

P_{2} = 1,000.

Hence, power absorbed by the resistors are as follows:

Powere absorbed by R_{1} = 5,000 W

Power absorbed by R_{2} = 1,000 W

Power absorbed by R_{3} = 1,500 W.

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

Single Variable Functions

Conics

Ordinary Differential Equations (ODEs)

Vector Spaces

Real Numbers

Separation Of Variables As Solution Method For Homogeneous Heat Flow Equation

Newton And Fourier Cooling Laws Applied To Heat Flow Boundary Conditions

Fourier Series

Derivation Of Heat Equation For A One-Dimensional Heat Flow

The Universe is composed of *matter* and *radiant energy*. *Matter* is any kind of *mass-energy* that moves with velocities less than the velocity of light. *Radiant energy* is any kind of *mass-energy* that moves with the velocity of light.

Periodic Table

Composition And Structure Of Matter

How Matter Gets Composed

How Matter Gets Composed (2)

Molecular Structure Of Matter

Molecular Shapes: Bond Length, Bond Angle

Molecular Shapes: Valence Shell Electron Pair Repulsion

Molecular Shapes: Orbital Hybridization

Molecular Shapes: Sigma Bonds Pi Bonds

Molecular Shapes: Non ABn Molecules

Molecular Orbital Theory

More Pj Problem Strings