Energy In One Quantum Of Light
Strings (SiPjAjk) = S7P3A32 Base Sequence = 12735 String Sequence = 12735 - 3 - 32
Determine the amount of energy in one quantum of light energy if its wavelength is 650 nm (nanometer).
S7P3A32 (Force - Push).
Pj Problem of Interest is of type force (push). Energy is the capacity to do work which is actualize by force. Light energy can do a pull or push work. The push work is more common. Hence the Pj Problem of Interest here is of type force-push.
One quantum of light energy is the same as the energy of one photon. This energy is represented as:
E = hν -------(1).
Where E is the energy of one photon; h is Planck's constant (0.66252 x 10-33 Js), an important fundamental constant of nature discovered by Max Planck (1858-1947); and ν is the frequency of light.
The frequency ν = c/λ -------(2)
Where c is the velocity of light (3 x 108); and &lamda; is the wavelength of light.
So, from equation (2):
ν = (3 x 108)/(650 x 10-9) = 4.62 x 1014 Hz Hertz cycles per second).
So from equation (1):
Energy of one quantum of light with 650nm wavelength
= hν = (0.66252 x 10-33)(4.62 x 1014) = 3.06 x 10-19 J.
The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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