Ideal Transformer

Figure 8.35 shows an Ideal Transformer. Show that: The apparent power of the primary coil equals the apparent power of the secondary coil.

The string:
S7P3A32 (Force - Push).
The math:

Pj Problem of interest is of type force. The transformer steps up or steps down voltage. Voltage, power and energy problems are force problems (force-push).
Basically, the transformer transfers power between AC circuits by either increasing or decreasing voltage or current. This transfer occurs magnetically instead of through a direct conductive connection.
The ideal transformer comprises two coils that are coupled together by means of a magnetic medium. The coil on the input side is called the primary, and the coil on the output side is called the secondary. The primary coil is wound so that it has n1 turns, while the secondary coil has n2 turns.
The turns ratio, N is defined as:
N = n2/n1 ----(1)
and sometimes as:
1:N
The relationship between N, voltages and currents of an ideal transformer are as follows:
V2 = NV1----(2)
I2 = I1/N----(3)
Where voltages and currents are rms values.
The ideal transformer multiplies a sinusoidal input voltage by a factor of N and divides a sinusoidal input current by a factor of N.
The transformer is a step-up transformer when N is greater than 1 and the output voltage is greater than the input voltage.
The transformer is a step-down transformer when N is less than 1 and the output voltage is less than the input voltage.
The transformer is called an isolation transformer when N = 1.
The isolation transformer is used to isolate two circuits from each other.
Apparent power in primary coil (V and I are rms values):
S1 = I1V1 = N(I2V2)/N = I2V2 = S2.
Hence, apparent power of the primary coil equals the apparent power of the secondary coil.
In other words, power is conserved in an ideal transformer

Blessed are they that have not seen, and yet have believed. John 20:29