Maximum Power Transfer By An Ideal Transformer Through Impedance Relection

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Maximum Power Transfer By An Ideal Transformer Through Impedance Relection

Given the ideal transformer of Figure 7.14, determine the turns ratio N =1/n that will provide maximum power transfer to the load.

**The strings**:
S_{7}P_{3}A_{32} (force-push).
**The math**:

Pj Problem of Interest is of type *force* (push).

**Equations: N = n _{2}/n_{1}
**

V_{2} = NV_{1}

I_{2} = I_{1}/N

Where N = turns ratio; n

V

I

Impedance reflection equation: Z

Maximum power transfer occurs when impedance matching or impedance reflection equation holds.

There is no complex parts of the load and internal resistance of the ideal transformer of figure 7.14

So, Z

And conjugate of Z

So, by the impedance reflection equation,

Maximum power transfer occurs when R

S0, 8 = 1800(1/n)

So, n

So, n = (225)

So, the turns ratio that will provide maximum power to the load = 1/15.

Math

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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