Power And Energy dissipated By An Electric Heater

Power And Energy dissipated By An Electric Heater
TECTechnics Classroom TECTechnics Overview

An Electric heater requires 23 A and 110 V, Calculate:
(a) The power it dissipates As heat or other losses
(b) The energy dissipated by the heater in 24 hours
(c) The cost of the energy if the power company charges 6 cents/kWh

The strings: S₇P₃A₃₂ (force - push).

The math:
Pj Problem of Interest is of type force (push).

Equations of interest: P = IV; E = IVt
Where P is power dissipated when a current I is flowing across a voltage V and E is the energy delivered in t secs by a circuit with a voltage source V and a current I.
(a) Current = 23 amperes, voltage = 110 V
So, power, P = 23 x 110 = 2530 watts = 2.53 kW.

(b) I = 23 A, V =110 V, t = 24 x 3600 secs Voltage = 12 V, current = 350 A. time = 3600secs. So, Energy , E = 23 x 110 x 24 x 3600 = 218.6 x 10⁶ =joules = 218.6 MJ.

(c) E = 23 x 110 x 24 = 60.720 kWh
So, Cost = 6 x 60.720 cents = 364 cents = $3.64.

Math

The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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Blessed are they that have not seen, and yet have believed. John 20:29