Conduction State Of An Ideal Diode

**Strings (S _{i}P_{j}A_{jk}) = S_{7}P_{4}A_{41} Base Sequence = 12735 String Sequence = 12735 - 4 - 41**

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Conduction State Of An Ideal Diode

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The circuit of figure 121.7 (a) consists of an ideal diode (the black triangle), voltages and resistors (R_{1}, R_{2}, R_{3}). The values of the voltages are as indicated in the diagram. R_{1} = 5 Ω, R_{2} = 10 Ω, R_{3} = 10 Ω.

(a) Is the diode conducting current?

(b) If resistor R_{2} is removed from the circuit, will the diode conduct current?

**The strings**:
S_{7}P_{4}A_{41} (Linear motion).
**The math**:

Pj Problem of Interest is of type *motion* (linear motion). Diode current is linear.

(a) Assume the diode does not conduct current

So, diode is replaced by an open circle (figure 121.7 (b)).

So, voltage across R_{2} = v_{1} = 12[R_{2}/R_{1} + R_{3}] --------voltage divider rule.

So, v_{1} = 12(10/15) = 8 V.

Now apply KVL to right-mesh of figure 121.7 (b):

So, v_{1} = v_{D} + 11

So, diode voltage, v_{D} = 8 - 11 = -3.

So, diode is reverse biased and therefore not conducting.

If initial assumption is that the diode is conducting

Then, diode is replaced by a short circuit (figure 121.7 (c)).

So, v_{1} = v_{2}

So, (12 - v_{1})/R_{1} = v_{1}/R_{2} + (v_{1} - 11)/ R_{3}

So, v_{1} = 8.75 V

So, v_{2} = v_{1} = 8.75 < 11

So, current is flowing in the reverse direction

So, diode is reverse baised and is not conducting.

(b) Yes. Diode will conduct if R_{2} is removed from the circuit.

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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