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How Deep Is The Well?

A rascally boy drops a stone into a well and listens for the sound of the splash. He finds that 6.5 secs elapse from the instance the stone is dropped until he hears the sound of the splash. Assuming that sound travels at 1152 ft/sec, how far below is the surface of the water?

**The string**: S_{7}P_{4}A_{41} (Linear Motion);
**The Math**:

Pj Problem of Interest (PPI) is of the type *motion*. Problems where distances traveled are sought are in general *motion problems*. In this case, it is the travel of the pebble that leads us to the depth of the well.

Let t_{1} be the time it took for the stone to hit the surface of the water in the well.

Let t_{2} be the time it took for the boy to hear the sound of the splash.

Then, t_{1} + t_{2} = 6.5 secs----(1).

Distance traveled by the stone = 16(t_{1})^{2}

Distance traveled by the sound from the splash = 1152t_{2}

Both distances measure d, the depth of the well to the surface of the water:

So, 16(t_{1})^{2} = 1152t_{2} ----(2)

So, 16(t_{1})^{2} = 1152(13/2 - t_{1})----(3)

because t_{1} = 6.5 - t_{2} (from equation 1).

Dividing equation (3) by 16, we have:

t_{1}^{2} = 72(13/2 - t_{1})

So, t_{1}^{2} + 72t_{1} - 468 = 0----(4)

Equation (4) is a quadratic equation

So, (t_{1} + 78)(t_{1} - 6) = 0

So, t_{1} = 6 is the sensible solution of equation (4)

So, t_{2} = 0.5 secs.

So, depth of well, d = 16(36) = 576 ft.

Also, d = 1152(0.5) = 576 ft (using t_{2})

Math

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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Derivation Of Volume Of A Sphere

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The Universe is composed of *matter* and *radiant energy*. *Matter* is any kind of *mass-energy* that moves with velocities less than the velocity of light. *Radiant energy* is any kind of *mass-energy* that moves with the velocity of light.

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