Maximum Range Of A Projectile

**Strings (S _{i}P_{j}A_{jk}) = S_{7}P_{4}A_{41} Base Sequence = 12735 String Sequence = 12735 - 4 - 41 **

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Maximum Range Of A Projectile

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A projectile is fired with an initial velocity of 2000 ft/sec. How long does it take to reach a target at maximum range?

**The string**:

S_{7}P_{4}A_{41} (Motion - Linear).
**The math**:

P_{j} Problem of Interest (PPI) is of type *motion*. Problems of distance traveled are *motion problems*. The linearity is because the focus is on the range (horizontal distance) of projectile.

Maximum range = V^{2}/32 (V is initial velocity). Also angle of fire = 45^{0}.

So, maximum range = (2000)^{2}/32 = Vtcos45

So, t = √2(10^{6})/(8 x 2000) = √2(62.5).

So, it take the projectile √2(62.5) secs to reach target at maximum range.

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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