﻿ Maximum Range Of Projectile

Maximum Range Of A Projectile

Strings (SiPjAjk) = S7P4A41     Base Sequence = 12735     String Sequence = 12735 - 4 - 41

Expressions Of Pj Problems
Maximum Range Of A Projectile
Math

A projectile is fired with an initial velocity of 2000 ft/sec. How long does it take to reach a target at maximum range?

The string:
S7P4A41 (Motion - Linear).
The math:
Pj Problem of Interest (PPI) is of type motion. Problems of distance traveled are motion problems. The linearity is because the focus is on the range (horizontal distance) of projectile.
Maximum range = V2/32 (V is initial velocity). Also angle of fire = 450.
So, maximum range = (2000)2/32 = Vtcos45
So, t = √2(106)/(8 x 2000) = √2(62.5).
So, it take the projectile √2(62.5) secs to reach target at maximum range. The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
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