﻿ Meridian Travel

Meridian Travel

String (SiPjAjk) = S7P4A42     Base Sequence = 12735     String Sequence = 12735 - 4 - 42

Expressions Of Pj Problems
Meridian Travel - Calculating Distance Traveled On A Meridian
Math If a man changes his latitude by 2 degrees when traveling along a meridian (figure 5.4). How far does he travel?

The string: S7P4A42 (Circular Motion).
{mi} = {traveler, transporter, land, air or sea (depending on mode of travel), travel accesories}
Si = transporter containership; land, air or sea containership (depending on mode of travel).
Independent Pj Problem (IPP): land, air or sea containership,
Dependent Pj Problems (DPP): transporter's containership, change (speed of transporter), identity (of traveler, transporter, etc).
Pj Problem of Interest (PPI) is motion (calculations of distances traveled are usually motion problems because the distance is a consequence of the motion. The calculation of an arbitrary distance without motion will be a containership problem.
The math:
The angle subtended by the arc AB in figure 5.4 at the center = 2o = 2(2π)/360 radians.
Arc length of AB = [2(2π)/360]OA where OA = R, radius of earth.
Circumference of earth = 25,000 miles = 2πR; So R = (25,000)/2π
So, arc AB = [2(2π)/360]x[(25,000)/2π] = (2/360)x25,000 = 139 approximately
So, Distance traveled by man is 2/360 of the earth's circumference = 139 miles approximately.

The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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