TECTechnics Classroom TECTechnics Overview
Pj Problems - Overview
Celestial Stars
The Number Line
Geometries
7 Spaces Of Interest - Overview
Triadic Unit Mesh
Creation
The Atom
Survival
Energy
Light
Heat
Sound
Music
Language
Stories
Work
States Of Matter
Buoyancy
Nuclear Reactions
Molecular Shapes
Electron Configurations
Chemical Bonds
Energy Conversion
Chemical Reactions
Electromagnetism
Continuity
Growth
Human-cells
Proteins
Nucleic Acids
COHN - Natures Engineering Of The Human Body
The Human-Body Systems
Vision
Walking
Behaviors
Sensors Sensings
Beauty
Faith, Love, Charity
Photosynthesis
Weather
Systems
Algorithms
Tools
Networks
Search
Differential Calculus
Antiderivative
Integral Calculus
Economies
Inflation
Markets
Money Supply
Painting
The rapid decomposition of sodium azide (NaN3) into its component elements inflates automotive air bags.
Given the following chemical decomposition of sodium azide:
2NaN3(s) ----> 2Na(s) + 3N2(g).
(a) How many moles of N2 are produced by the decomposition of 1.500 moles of NaN3?
(b) Calculate grams of NaN3 needed to produce 10 g of N2.
(c) Calculate grams of NaN3 needed to produce 10 ft3 of nitrogen gas if the gas has a density of 1.25 g/L.
The strings:
S7P6A66 (interaction - chemical).
S7P1A15 (containership - mass).
The math:
Although we are calculating , mass, grams and moles, the chemical reaction is the reason for the calculation. So Pj Problem of Interest is of type interaction (chemical).
(a) 2 moles of NaN3 reacts with 3 moles of N2
So, 1.500 moles of NaN3 will react with (1.500 x 3)/2 = 2.25 moles of N2
(b)Molar mass of nitrogen = 14 x 2 = 28 g
28 g is weight of 1 mole of N2
So, 10 g is the weight of 10/28 moles = 0.357 moles of N2
3 moles of N2 is formed by 2 moles of NaN3
So, 0.357 mol of N2 is formed by (0.357 x 2)/3 = 0.238 mol of moles of NaN3
Molar mass of moles of NaN3 = 23 + 42 = 65 g
1 mole of NaN3 weighs 65 g
So, 0.238 of NaN3 weighs (0.238 x 65) = 15.5 g.
(c) 1 Liter = 0.0353 ft3
So, 10 ft3 of N2 = 10/0.0353 Liters = 283 L.
Mass of 283 L of N2 = 1.25 x 283 = 353.75 g
Molar mass of N2 = 14 x 2 = 28
28 g of N2 is the weight of 1 mole of N2
So, 353.75 g is the weight of 353.75/28 = 12.64 moles
3 moles of N2 is formed from 2 moles of NaN3
So, 12.64 moles of N2 is formed by (2 x 12.64)/3 oles of NaN3 = 8.43 moles
Molar mass of NaN3 = 23 + 42 = 65
1 mole of NaN3 weighs 65 g
So, 8.43 moles of NaN3 weighs 8.43 x 65 = 548 g.
The point . is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.
Single Variable Functions
Conics
Ordinary Differential Equations (ODEs)
Vector Spaces
Real Numbers
Separation Of Variables As Solution Method For Homogeneous Heat Flow Equation
Newton And Fourier Cooling Laws Applied To Heat Flow Boundary Conditions
Fourier Series
Derivation Of Heat Equation For A One-Dimensional Heat Flow
The Universe is composed of matter and radiant energy. Matter is any kind of mass-energy that moves with velocities less than the velocity of light. Radiant energy is any kind of mass-energy that moves with the velocity of light.
Periodic Table
Composition And Structure Of Matter
How Matter Gets Composed
How Matter Gets Composed (2)
Molecular Structure Of Matter
Molecular Shapes: Bond Length, Bond Angle
Molecular Shapes: Valence Shell Electron Pair Repulsion
Molecular Shapes: Orbital Hybridization
Molecular Shapes: Sigma Bonds Pi Bonds
Molecular Shapes: Non ABn Molecules
Molecular Orbital Theory
More Pj Problem Strings