Titration - Neutralization Of Hydrobromic Acid By Calcium Hydroxide

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Titration - Neutralization Of Hydrobromic Acid By Calcium Hydroxide

*Titration* is the process whereby a solution of known concentration called the *standard solution* is combined with a solution of unknown concentration in order to determine the unknown concentration or the quantity of solute in the unknown. An *indicator* is used to show the *end point* of the titration. This end point coincides with the *equivalent point*, the point at which equivalent quantities of reactants are brought together stoichiometrically.

A sample of solid Ca(OH)_{2} is stirred in water at 30^{0}C until the solution contains as much dissolved Ca(OH)_{2} as it can hold. A 100-mL sample of this solution is withdrawn and titrated with 5 x 10^{-2} M HBr. It requires 48.8 mL of the acid solution for neutralization.

What is the molarity of the Ca(OH)_{2} solution?

What is the solubility of Ca(OH)_{2} in water, at 30^{0}C in grams of Ca(OH)_{2} per 100 mL of solution?

**The strings**:
S_{7}P_{6}A_{66} (interaction - chemical).

S_{7}P_{1}A_{15} (containership - mass).
**The math**:

Although we are calculating, mass, grams and moles, the chemical reaction is the reason for the calculation. So Pj Problem of Interest is of type *interaction* (chemical).

**(a)** Chemical equation:

2HBr + Ca(OH)_{2} -------> CaBr_{2} + 2H_{2}O

0.05 mol in 1 Liter of HBr (concentration of HBr)

So, (0.05)(0.0488) = 0.00244 mol in 48.8 mL

Mole ratio HBr:Ca(OH)_{2} = 2:1 (from balanced equation)

So, mol of Ca(OH)_{2} = 0.00244/2 = 0.00122 mol

So, 0.00122 mol of Ca(OH)_{2} in 0.100 L

So, 0.00122/0.100 = 0.0122 in 1 L = 0.0122 M = 1.22 x 10^{-2} M.
**(b)**

Molar mass of Ca(OH)_{2} = 40 + 32 + 2 = 74 g

So, mass of Ca(OH)_{2} in 100 mL = 0.00122 x 40 = 0.0903 g

So, solubility of Ca(OH)_{2} in 100 mL = 0.0903 g.

Math

The *point* **.** is a mathematical abstraction. It has negligible size and a great sense of position. Consequently, it is front and center in abstract existential reasoning.

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